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If the sum of first 7 terms of an A.P. is 49 and that of its first 17 terms is 289, find the sum of first n terms of the A.P.
Concept: Sum of First ‘n’ Terms of an Arithmetic Progressions
In the given figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the shaded region.

Concept: Areas of Sector and Segment of a Circle
If the quadratic equation px2 − 2√5px + 15 = 0 has two equal roots then find the value of p.
Concept: Nature of Roots of a Quadratic Equation
In the following figure, in ΔPQR, seg RS is the bisector of ∠PRQ. If PS = 6, SQ = 8, PR = 15, find QR.

Concept: Similar Triangles
Radha deposited ₹ 400 per month in a recurring deposit account for 18 months. The qualifying sum of money for the calculation of interest is ______.
Concept: Mathematics of Recurring Deposit (R.D.)
In the given figure, if A(P-ABC) = 154 cm2 radius of the circle is 14 cm, find
(1) `∠APC`
(2) l ( arc ABC) .

Concept: Circumference of a Circle
Given, `x + 2 ≤ x/3 + 3` and x is a prime number. The solution set for x is ______.
Concept: Solving Algebraically and Writing the Solution in Set Notation Form
Solve the following inequation, write the solution set and represent it on the real number line.
`5x - 21 < (5x)/7 - 6 ≤ -3 3/7 + x, x ∈ R`
Concept: Representation of Solution on the Number Line
A manufacturing company prepares spherical ball bearings, each of radius 7 mm and mass 4 gm. These ball bearings are packed into boxes. Each box can have a maximum of 2156 cm3 of ball bearings. Find the:
- maximum number of ball bearings that each box can have.
- mass of each box of ball bearings in kg.
(Use π = `22/7`)
Concept: Surface Area of a Sphere
A manufacturing company prepares spherical ball bearings, each of radius 7 mm and mass 4 gm. These ball bearings are packed into boxes. Each box can have a maximum of 2156 cm3 of ball bearings. Find the:
- maximum number of ball bearings that each box can have.
- mass of each box of ball bearings in kg.
(Use π = `22/7`)
Concept: Surface Area of a Sphere
Prove the identity (sin θ + cos θ)(tan θ + cot θ) = sec θ + cosec θ.
Concept: Trigonometric Identities
Which of the following equations has 2 as a root?
Concept: Nature of Roots of a Quadratic Equation
Prove the following trigonometry identity:
(sin θ + cos θ)(cosec θ – sec θ) = cosec θ ⋅ sec θ – 2 tan θ
Concept: Trigonometric Identities
The roots of equation (q – r)x2 + (r – p)x + (p – q) = 0 are equal.
Prove that 2q = p + r; i.e., p, q, and r are in A.P.
Concept: Nature of Roots of a Quadratic Equation
Given that the sum of the squares of the first seven natural numbers is 140, then their mean is ______.
Concept: Problems Based on Numbers
Using step-deviation method, find mean for the following frequency distribution:
| Class | 0 – 15 | 15 – 30 | 30 – 45 | 45 – 60 | 60 – 75 | 75 – 90 |
| Frequency | 3 | 4 | 7 | 6 | 8 | 2 |
Concept: Mean of Grouped Data
A bag contains 3 red and 2 blue marbles. A marble is drawn at random. The probability of drawing a black marble is ______.
Concept: Probability - A Theoretical Approach
If x, y and z are in continued proportion, Prove that:
`x/(y^2.z^2) + y/(z^2.x^2) + z/(x^2.y^2) = 1/x^3 + 1/y^3 + 1/z^3`
Concept: Proportion
A mixture of paint is prepared by mixing 2 parts of red pigments with 5 parts of the base. Using the given information in the following table, find the values of a, b and c to get the required mixture of paint.
| Parts of red pigment | 2 | 4 | b | 6 |
| Parts of base | 5 | a | 12.5 | c |
Concept: Direct Applications
While factorizing a given polynomial using the remainder and factor theorem, a student finds that (2x + 1) is a factor of 2x3 + 7x2 + 2x – 3.
- Is the student’s solution correct in stating that (2x + 1) is a factor of the given polynomial?
- Give a valid reason for your answer.
Also, factorize the given polynomial completely.
Concept: Factorising a Polynomial Completely After Obtaining One Factor by Factor Theorem
